The formula to get the coordinates of the vertex when the graph strikes out the symmetry axis is interpreted as the vertex formula. In mathematics, the point of the vertex is depicted as (h, k). The formula to get the vertex is illustrated below:

**(h, k) = ( – b/2*a, – D/ 4*a)**

In the above-illustrated formula,

** D= b*b – 4* a*c** or, the formula for vertex can also be illustrated as,

*. By applying these formulas, one can get the value for the given vertex.*

**( -b/ 2*a, c – b*b / 4*a )**Contents

## Few Examples of Vertex Formula

The intention of examples helps to clarify statements. With the assistance of examples, the learners will get better and clear concepts of the given topic. Here, we will be illustrating some of the examples to enable the learners in solving problems based on this.

**Example 1:** There is an equation provided,

** Y= zx*x + q*x -1**. One has to get the vertex for this.

**Solution:**

We have been given the equation,

** Y = zx*x + q * x -1**,

We will correlate this with,

*Y = ax*x + b*x + c*

We will have now,

*a = z*

*b = q*

*c = -1*

Now, we will get the ** D** now

*D = b*b – 4*a*c*

By settling all the values, we will have

*D = q*q + 4*z*

Now, we will have to settle all the values in the vertex formula,

*(h, k) = ( -b/2a, – D/ 4a)*

*= ( -q/2z, – ( q*q + 4 z )/ 4z )*

**Example 2 :** There is a parabolic equation provided, *y = x*x + 15*x + 222*

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**. One has to get the vertex.**

**Solution:**

We have been provided with the equation,

** y = x*x + 15*x + 222**,

We will correlate this with,

** Y= ax*x + b*x + c**,

*a= 1*

*b = 15*

*c = 222*

Now, we will have to get ** D**,

*D = b*b – 4*a*c*

**= 15*15 – 4*1*222**

= -663

Now, we will settle all these values into the vertex formula,

We will get,

*(h, k) = ( -15/2, +663/4)*

## What is the Area of a Square?

The item’s area is the amount of expanse it takes up. It’s the area that every shape can occupy. The area of square** **can be interpreted as the space enclosed by all four sides of that square. In any square, all four walls are of identical height. Accordingly, the area of the square used to be identical to the walls of the square.

The formula to get the area of the square is illustrated below ;

area of the square= wall * wall

## Few Examples of the Area of a Square

Now, we will be illustrating some of the examples to provide more clear concepts about the specific topic and assist the learners in solving further problems, based on this topic.

**Example 1:** There is a square provided with the length of the wall w. One has to get the area of this provided square.

**Solution:**

We have been provided with the length of a wall. Since we already infer that all the walls of a square are identical, the other 3 walls of this square will also be w.

Now, we have been provided with the formula to get the area.

*Area = wall * wall*

We will settle all the values into the formula,

*Area = w *w*

We will get the area of the square as * w*w* square units.

**Example 2:** There is a square given with a wall of the length of ** 50.2**. One has to get the area of this square.

**Solution:**

We have been provided with the length of the wall and that is,

*50.2*

Now, we will settle this in the formula,

* Area = 50.2 * 50.2* square units

To learn further about this particular topic, in a very fun and inventive way, one should surely visit Cuemath. One can also learn about several distinct topics too.